After he withdraws $50.00 in cash the bank reconciliation shows that Ryan would have: $1 501.98 in bank balance.
<h3>What is the solution to the above?</h3>
Add all the deposits
- 28 x 10 = 280
- 9 x 5 = 45
- 20 x 0.25 = 5
- 85 x 0.10 = 8.5
- 32 x 0.01 = 0.32
Total = $338.82
Add the checks
654.24 + 100.00 + 458.92
= $1,213.16
Total amount deposited is: Cash + Check
1,213.16 + 338.82
Total Deposit = $1,551.98
Less withdrawal of $50
$1,551.98 - $50
Balance left = 1 501.98
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Full Question:
Ryan Massey wants to deposit the following into his savings account: 28 ten-dollar bills, 9 five-dollar bills, 20 quarters, 85 dimes, 32 pennies, and three checks for $654.24, $100.00, and $458.92. He wants to receive $50.00 in cash.
How much cash would he lave left after he withdraws $50.00 in cash?
Answer:
I would say triangle. But I am not completely sure!
Step-by-step explanation:
Hope this helps!
<span>The answer is 90,000</span>
Answer:
The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample mean is given by,

And the standard deviation of the distribution of sample mean is given by,

The information provided is:
<em>μ</em> = 144 mm
<em>σ</em> = 7 mm
<em>n</em> = 50.
Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:


*Use a <em>z</em>-table for the probability.
Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.