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ioda
3 years ago
15

100 points its most of my points PLS HELP ME IM LOSING ALOT OF POINTS

Mathematics
1 answer:
rosijanka [135]3 years ago
3 0

Hello there mate☺️,

The answer for your question is in the attached images .

✍️ <em>By </em><em>Benjemin</em><em> ☺️</em>

You might be interested in
Please help me !!!!!!​
bearhunter [10]

Second one is correct, The value of -a - c is positive

See, from the number line a = -6 and c = 2

Now, -a - c

= -(-6) -(2)

= +6 - 2 = 4

Which is true...

5 0
3 years ago
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
3 years ago
What is the answer to this problem-k-6-7k+20=-2
STatiana [176]

Answer:

K=2 that is the answer

6 0
3 years ago
Your answer should be in the formp (x) +k/x where p is a polynomial and k is an integer. 5x^2+x+7/x
Alona [7]

Answer:

p(x) + \frac{k}{x} = 5x + 1 + \frac{7}{x}

Step-by-step explanation:

Given

\frac{5x^2 + x + 7}{x}

Required

Express in form of p(x) + \frac{k}{x}

\frac{5x^2 + x + 7}{x}

The above can be expressed as:

p(x) + \frac{k}{x} = \frac{5x^2 + x + 7}{x}

p(x) + \frac{k}{x} = \frac{5x^2}{x} + \frac{x}{x} + \frac{7}{x}

p(x) + \frac{k}{x} = 5x + 1 + \frac{7}{x}

By comparison:

p(x) = 5x + 1 and k = 7

3 0
3 years ago
5x2 - 7x + 2 - 3x2 + 4x - 8
sammy [17]

Answer:

this is an example u can try it out

Step-by-step explanation:

mark me has brainly list

6 0
3 years ago
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