Question

Point X is located at (2, −6), and point Z is located at (0, 5). Find the y value for the point Y that is located one over five the distance from point X to point Z.
−3.6
−3.8
−4
−4.2

Answer 1

The answer would be B, -3.8.
HOPE THIS HELPS! ^_^

Answer 2

Answer:

The value of Y is -3.8

B is correct.

Step-by-step explanation:

Point X is located at (2, −6), and point Z is located at (0, 5)

The point Y that is located one over five the distance from point X to point Z

We can say XY is one-fifth of XZ

If we find the ratio of XY:YZ  then 1:4

Using section formula,

$(x,y)\rightarrow (\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n})$

We need to find y coordinate of Y

$y\rightarrow \dfrac{5\cdot 1-6\cdot 4}{1+4}$

$y\rightarrow \dfrac{5-24}{5}$

$y\rightarrow \dfrac{-19}{5}$

$y\rightarrow -3.8$

Hence, The value of Y is -3.8