Answer:
77
Step-by-step explanation:
Answer:
In this problem, I can not tell what is V, so I will answer it in a general way.
A polynomial is something of the form:
a*x^5 + b*x^4 + c*x^3 + d*x^2 + e*x + f
a, b, c, d, e, and f are real numbers and constant.
Where the degree of the polynomial is equal to the greatest power (in this case 5).
You write:
4x^2 + 3Vx + 5
Now, if V is a real number, then we have that this is a polynomial of degree 2.
Because we can write this as:
4*x^2 + (3V)*x + 5
So the answer is true.
Now, if V is a variable or an operation, the answer will be false.
Answer:
v = 2q
Step-by-step explanation:
If this is all is given in the question, then the answer is an equation. If there are numbers given, then plug the numbers into the equation to solve.
A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>