Daniel Potter bought a new car for $20,000.00. Two years later, he wanted to sell it. He was offered $14,650.00 for it. If he so ld it for that amount, what was his depreciation rate?
2 answers:
Answer: 13.375% per year Explanation: 1) Depreciation is the loss of value: $ 20,000.00 - $ 14,650.00 = $ 5,350 2) The percent of depreciation is amount of the depreciation divided by the value of the car when purchased, times 100. That is (5,350 / $ 20,000) * 100 = 26.75 % 2) The rate is percent of depreciation per year: depreciation rate = % of depreciation / number of years = 26.75% / 2 = 13.375% per year.
First compute the different of the price like this:
$20,000.00-$14,650.00=5350$<span>
Then divide like this:
</span>
Now compute the percentage like this:
In order to compute the rate, divide by the number of years we get:
The rate of depreciation is
.
<span>
</span>
You might be interested in
20/ X= 100 ⇒ X= 20/100 (inverse operation) ⇒ X= 1/5Final answer: X= 1/5
Answer:
it equals to 1032000
Step-by-step explanation:
because 3000 x 344 = 1032000
Answer:
coefficent matrix
Step-by-step explanation:
P. 366
"If the column of constant terms is not included, the matrix reduces to that of the coefficent matrix of the system"
-1 -3 -1
9 -9 -1
-1 -3 4
<span><span>29, 31, 33, & 25. Those are all odd and if added up equal 128 </span><span> </span></span>
Hmm, I think your answer would be 3x ≥ -6 Let me know if this helps!