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2 years ago

Select the correct statement(s) regarding DCE and DTE interfaces.

Computers and Technology

1 answer:

timama [110]2 years ago

6 0

Answer:

The correct statement regarding DCE and DTE interfaces is:

c. DTE and DCE describes the interface and direction of data flow between devices; a single device may have both types of interfaces.

Explanation:

DTE stands for Data Terminal Equipment. It is a device that initiates or controls a device's serial connection. The term DCE stands for Data Communications Equipment. It is a device that is used to a modem or other communication interfaces to the DTE device. DTE is a communication receptor, while DCE is a communication broadcaster or distributor.

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Compute the bitwise XOR between 10010100 and 11101010.

Contact [7]

Answer:

The resultants bits for two strings are 0111 1110

Explanation:

Given details:

two pair of strings are

10010100

11101010

comparing two pair of strings, then perform XOR operation

Rules to follow for XOR

If both the bits are same then resultant is zero 0 and if bits are different resultant is one

XOR operation:

10010100

11 1 01010

-------------

01111110

The resultants bits for two strings are 0111 1110

8 0

3 years ago

Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t

Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

#include<stdio.h>

int main(int argc, char** argv){

//creating pointer to read a file

FILE * fp;

char * line = NULL;

size_t len = 0;

ssize_t read;

int i=0;

//opening a file

fp = fopen(argv[1], "r");

//handling the error condition

if (fp == NULL){

printf("File not found..!!");

return 0;

}

int moreThan50 =0;

//reading a file line by line

while ((read = getline(&line, &len, fp)) != -1) {

i = 0;

if(read >= 50){

moreThan50++;

}

while(i < read){

if(line[i]!='\n'){

if(i%50 == 0){

printf("\n%c",line[i]);

}else{

printf("%c",line[i]);

}

i++;

}

printf("\nTotal lines over 50 chars: %d\n",moreThan50);

printf("Offending Lines: ");

for(i=1;i<=moreThan50;i++)

printf("%d, ",i);

fclose(fp);

return 0;

}

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0

1 year ago

Write code which takes a sentence as an input from the user and then prints the length of the first word in that sentence.

Afina-wow [57]

import java.util.Scanner;

public class U2_L3_Activity_Four {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.println("Enter a sentence.");

String sent = scan.nextLine();

int count = 0;

for (int i = 0; i < sent.length(); i++){

char c = sent.charAt(i);

if (c != ' '){

count++;

}

else{

break;

}

System.out.println("The first word is " + count +" letters long");

}

We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!

7 0

2 years ago

PLS HURRY Look at the image below

fenix001 [56]

Answer:

one sec

what is that called?

if you have more than one try

then you should just take an "EDUCATIONAL GUESS"

it's a 50/50 chance

just take it

Explanation:

8 0

3 years ago

All changes

Vsevolod [243]

You should get up and move every 30 minutes

Hope this helps

-scav

7 0

3 years ago