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2 years ago

Find the difference in the given lengths of the polygons . (7x + 2) units (6x - 5) units .

Mathematics

1 answer:

Tom [10]2 years ago

7 0

Answer:

Difference in the lengths of the polygons is (x + 7) units.

Step-by-step explanation:

Lengths of the given polygon = (7x + 2) units and (6x - 5) units

Therefore, difference in the given lengths = (7x + 2) - (6x - 5)

= (7x - 6x) + (2 + 5)

= x + 7

Therefore, difference in the lengths of the polygons is (x + 7) units.

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Does the point (0,4) make either equations y=-2x and y=x+3 true? Explain.

Nikolay [14]

Answer:

Neither

Step-by-step explanation:

To verify, we substitute the values in the equations:

$y = -2x\\y = -2 \times 0\\y = 0$

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

$y = x+3\\y= 0+3\\y = 3$

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

5 0

3 years ago

In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product,

Vadim26 [7]

Answer: 0.2872

Step-by-step explanation:

Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.

i.e. n= 1000 and x= 260

⇒ Sample proportion : $\hat{p}=\dfrac{260}{1000}=0.26$

z-value for 95% confidence interval : $z_c=1.960$

Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-

$\hat{p}+ z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.26+ (1.96)\sqrt{\dfrac{0.26(1-0.26)}{1000}}$

$=0.26+ (1.96)(0.01387)=0.26+0.0271852=0.2871852\approx0.2872$

∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872

7 0

3 years ago

System of equations <br> Elimination<br> please help i am stuck!!

Anika [276]

-5x = - 7 because -6x plus x is -5x and use elimination to get rid of the -3y so you end up with -5x = -7

7 0

2 years ago

How many terms are there in a geometric series if the first term is 4, the common ration is 3 and the sum of the series is 160

Marina CMI [18]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
S_n=160
\end{cases}$

$\bf 160=4\left( \cfrac{1-3^n}{1-3} \right)\implies 160=4\left( \cfrac{1-3^n}{-2} \right)\implies 160=-2(1-3^n)
\\\\\\
160=2(3^n-1)\implies \cfrac{160}{2}=3^n-1\implies 80=3^n-1
\\\\\\
81=3^n~~
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^4=3^n\implies 4=n$

3 0

2 years ago

Hey just doing this so you can get some points

lara31 [8.8K]

Answer:

thank you very much xoxo

4 0

2 years ago