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2 years ago

Find the difference in the given lengths of the polygons . (7x + 2) units (6x - 5) units .

Mathematics

1 answer:

Tom [10]2 years ago

7 0

Answer:

Difference in the lengths of the polygons is (x + 7) units.

Step-by-step explanation:

Lengths of the given polygon = (7x + 2) units and (6x - 5) units

Therefore, difference in the given lengths = (7x + 2) - (6x - 5)

= (7x - 6x) + (2 + 5)

= x + 7

Therefore, difference in the lengths of the polygons is (x + 7) units.

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The small submarine is at –1,320 feet in relation to sea level. The submarine needs to be 180 feet below sea level in 60 minutes

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Answer:

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3 years ago

Write the linear equation that gives the rule for this table.

stiks02 [169]

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3 years ago

The offices of president, vice president, secretary, and treasurer for an environmental club will be filled from a pool of 15c

Alexus [3.1K]

Answer:

a) 5.13% probability that all of the offices are filled by members of the debate team

b) 2.56% probability that none of the offices are filled by members of the debate team

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the people are chosen is important, since the first person is the president, the second is the vice president and so on... So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

(a) What is the probability that all of the offices are filled by members of the debate team?

Desired outcomes:

4(president, vice president, secretary, and treasurer) offices from a set of 8(candidates of the members debate team).

$D = P_{(8,4)} = \frac{8!}{(8-4)!} = 1680$

Total outcomes:

4 offices from a set of 15 candidates.

$T = P_{(15,4)} = \frac{15!}{(15-4)!} = 32760$

Probability:

$P = \frac{D}{T} = \frac{1680}{32760} = 0.0513$

5.13% probability that all of the offices are filled by members of the debate team

(b) What is the probability that none of the offices are filled by members of the debate team?

Desired outcomes:

4(president, vice president, secretary, and treasurer) offices from a set of 7(candidates who are not of the members debate team).

$D = P_{(7,4)} = \frac{7!}{(7-4)!} = 840$

Total outcomes:

4 offices from a set of 15 candidates.

$T = P_{(15,4)} = \frac{15!}{(15-4)!} = 32760$

Probability:

$P = \frac{D}{T} = \frac{840}{32760} = 0.0256$

2.56% probability that none of the offices are filled by members of the debate team

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3 years ago

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Hello,

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3 years ago