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3 years ago

Find the difference in the given lengths of the polygons . (7x + 2) units (6x - 5) units .

Mathematics

1 answer:

Tom [10]3 years ago

7 0

Answer:

Difference in the lengths of the polygons is (x + 7) units.

Step-by-step explanation:

Lengths of the given polygon = (7x + 2) units and (6x - 5) units

Therefore, difference in the given lengths = (7x + 2) - (6x - 5)

= (7x - 6x) + (2 + 5)

= x + 7

Therefore, difference in the lengths of the polygons is (x + 7) units.

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Perform the multiplication, (7x2+a2)(x2–3a2)

aksik [14]

Answer:

The given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Step-by-step explanation:

Given expression is $(7x^2+a^2)(x^2-3a^2)$

To find the multiplication of the given expression :

$(7x^2+a^2)(x^2-3a^2)$

By using the distributive property to solve the given expression as below

$(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)$

$=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2$

$=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$=7x^4-21x^2a^2+a^2x^2-3a^4$

Adding the like terms in the above expression we get

$=7x^4-20x^2a^2-3a^4$

Therefore $(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Therefore the given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

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Find the perimeter of the rectangle whose coordinates are A (5, 3), B (8, 3), C

MaRussiya [10]

Answer:

Step-by-step explanation:

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3 years ago

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Reptile [31]

8 and 12 are separated by 1 line, and they have a difference of 4 units, so..

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3 years ago

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allochka39001 [22]

Answer: 1st is 180$ sorry if I’m wrong

Step-by-step explanation:

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natka813 [3]

Answer:

Step-by-step explanation:

Cross multiplying

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z = 336/5

Or mixed fraction z= 67(1/5)

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3 years ago

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