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Mars2501 [29]
3 years ago
6

s.Lewis has a net spendable income of $2,000 per month. He sets up the following transportation budget for himself. 3. Transport

ation (15% - 20%) 400 a. Car payments 210 b. Gas/Oil 120 c. Insurance 60 d. License/Registration 8 e. Taxes 2 f. Maintenance/Repair What has Lewis done wrong? A. He budgeted more than the maximum recommended amount of money for transportation. B. He budgeted less than the minimum recommended amount of money to cover gas for the month. C. He has more money in the subcategories than he budgeted for in the main category. D. He has not budgeted for all of the expenses in the subcategories.
Mathematics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

D.He has not budgeted for all of the expenses in the subcategories.

Step-by-step explanation:

Transportation Budget :  400

a. Car payments 210

b. Gas/Oil 120

c. Insurance 60

d. License/Registration 8

e. Taxes 2

f. Maintenance/Repair

Lewis did not budget the Maintenance/Repair subcategory,  because there is no price or cost indicator next to it.

Therefore, the corrct answer is option

D.He has not budgeted for all of the expenses in the subcategories.

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Step-by-step explanation:

Let

{1/(x+2y)} = u -----Eqn(1)

{1/(x-2y)} = v ------Eqn(2)

So, given equation can be rewritten as

⇛6u + 5v = -3 ---Eqn(3)

⇛3u + 7v = -6 -----Eqn(4)

On multiply equation (4) by 2, we get

⇛6u + 14v = -12 -----Eqn(5)

On subtracting equation (3) from equation (5), we get

⇛9v = -9

⇛v = -9/9

⇛v = -1 ----Eqn(6)

Put value of v in equation (3), we get

6u + 5v = -3

⇛6u + 5 * (-1) = -3

⇛6u -5 = -3

⇛6u = -3 + 5

⇛6u = 2

⇛u = 2/6

⇛u = (2÷2)/(6÷2)

⇛u = 1/3 -----Eqn(7)

Now, substituting value of u and v in equation (1) and equation (2), we get

{1/(x+2y)} = 1/3 and {1/(x-2y)} = -1

⇛x + 2y = 3 -----Eqn(8)

⇛x - 2y = -1 -------Eqn(9)

Now, add equation (8) and equation (9) , we get

⇛2x = 2

⇛x = 2/2

<h3>⇛x = 1 -----Eqn(10)</h3>

On substituting x = 1 in equation (8), we get

x + 2y = 3

⇛ 1 + 2y = 3

⇛2y = 3 - 1

⇛2y = 2

⇛y = 2/2

<h3>⇛y = 1 ------Eqn(11)</h3>

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5(2x - y) = 10x - 5y and it is not equal to 15x - 5y.

(using distribution property)

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