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nataly862011 [7]
2 years ago
11

The expression x+8x+10 is modeled below

Mathematics
2 answers:
Vladimir [108]2 years ago
7 0

Answer:

6 to be added

Step-by-step explanation:

If 6 is added, it would complete the square.

Hope it helps.

adoni [48]2 years ago
3 0

Answer:

  add 6 unit tiles

Step-by-step explanation:

The square is completed when the algebra tile grid pattern is a square. This one will be a square when 6 more unit tiles are added to fill the empty spaces at the bottom right.

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It is a trapezium, I guess

Step-by-step explanation:

To know more see the picture attached

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I need help with 50. I don't know how to figure it out
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The answer is in the picture

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On Monday, Takira counted 75 splatters of bird droppings on her car. On Tuesday afternoon, she counted 21 more. What is the perc
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Answer:

28%

Step-by-step explanation:

percent change in the number of bird droppings = increase in splatters / splatters counted on Monday x 100

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2 years ago
1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene
rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

<em>x² + y²-8x + 10y + 16 = 0 </em>

<em>Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0 </em>

<em> </em>

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

<em>x² + y² + x + 18y + 33 = 0 </em>

<em>Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0</em>

4 0
2 years ago
There are fifteen teams in a high school baseball league. How many different orders of finish are possible for the first four ​p
ankoles [38]
There are 32,760 different orders for the first four positions.

This is a permutation where repetition is not allowed; the formula for that is:

_nP_r=\frac{n!}{(n-r)!}

For our problem, we have:
_{15}P_4=\frac{15!}{(15-4)!}=\frac{15!}{11!}=32760
3 0
3 years ago
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