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scZoUnD [109]
3 years ago
8

What is -3/1 2 -2 3.​

Mathematics
1 answer:
zlopas [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Exact Form:

17/6

Decimal Form:

2.83

Mixed Number Form:

2  5/6  

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Find the zeros of x^2+4x=-10 using the quadratic formula
ipn [44]
X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

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3 years ago
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Someone try this who smart
Lelechka [254]

Answer:

Step-by-step explanation:

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2 years ago
Equation of the line contains the points (-3,2) and (5,-5)
makkiz [27]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

(x_ {1}, y_ {1}): (- 3,2)\\(x_ {2}, y_ {2}) :( 5, -5)

So the slope is:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-5-2} {5 - (- 3)} = \frac {-7} {5 + 3} = - \frac {7} {8}

Thus, the equation of the line is of the form:

y = - \frac {7} {8} x + b

We substitute one of the points and find "b":

2 = - \frac {7} {8} (- 3) + b\\2 = \frac {21} {8} + b\\b = 2- \frac {21} {8}\\b = \frac {16-21} {8}\\b = - \frac {5} {8}

Finally, the equation is:

y = - \frac {7} {8} x- \frac {5} {8}

Answer:

y = - \frac {7} {8} x- \frac {5} {8}

6 0
3 years ago
Answer number 14. It’s very difficult for me and i need some help.
professor190 [17]

Answer:

1201.2 in (100.1ft)

Step-by-step explanation:

A scale model represents a ratio. All sides must be shrunk or increased based on a constant value. In this case the ratio of the model is 1/13 the size of the original giving us a 1:13 ratio. So each side of your scale model must be multiplied by 13 to find the real value of the side.

First convert all units to inches then divide the width of the real windmill by the width of the scale model (both in inches) you will see the answer is 13. Multiply the inch values of all sides of your model by 13 and this gives you the proportional value of each side of the real windmill in relation to the scale model.

5 0
2 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
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