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3 years ago

PLEASE HELP ASAP!!! THIS IS MY LAST QUESTION!! SHOW WORK!! DUE IN 5 MINS

Mathematics

1 answer:

IrinaK [193]3 years ago

4 0

Answer:

Show questions

Step-by-step explanation:

common sense

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Here's a list of numbers : 13, 27 ,81, 21 ,43, 48 ,23, 39 ,45 From this list, write down a.) The even number b.) The square numb

vazorg [7]

Answer:

48 is the even number

81 is the square number

13 43 23 are the prime numbers

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4 years ago

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Fruit -o- Rama sells dried pineapple for $0.25 per ounce.Mags spent a total of $2.65 on pineapple. How many ounces did she buy?

Andrews [41]

The answer is 10.6 oz.

2.65 / 0.25 = 10.6

Hope this helps! If so, please mark brainliest!

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3 years ago

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7x - 20 = 2x - 3(3x + 2)

kirill [66]

Answer:

7x-20=2x-3(3x+2)

We move all terms to the left:

7x-20-(2x-3(3x+2))=0

We calculate terms in parentheses: -(2x-3(3x+2)), so:

2x-3(3x+2)

We multiply parentheses

2x-9x-6

We add all the numbers together, and all the variables

-7x-6

Back to the equation:

-(-7x-6)

We get rid of parentheses

7x+7x+6-20=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

Step-by-step explanation:

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3 years ago

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Write 124 in scientific notation.

Artemon [7]

Answer:

Step-by-step explanation:

Write 124 in scientific notation.

Then, in scientific notation, 124 is written as 1.24 × 102. Actually, converting between "regular" notation and scientific notation is even simpler than I just showed, because all you really need to do is count decimal places.

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3 years ago

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Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

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3 years ago