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2 years ago

PLEASE HELP ASAP!!! THIS IS MY LAST QUESTION!! SHOW WORK!! DUE IN 5 MINS

Mathematics

1 answer:

IrinaK [193]2 years ago

4 0

Answer:

Show questions

Step-by-step explanation:

common sense

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the length of a rectangle is 7 yd more than 5 times the width. the perimeter is 150 yd. find the length and the width.

Vaselesa [24]

P = 2(L + W)
P = 150
L = 5W + 7

150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width

L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length

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2 years ago

Pls help. Cindi wants to cover the top and sides of this box with glass tiles that

Marat540 [252]

Answer:

300 square centimeters

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2 years ago

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How many solutions does the system have?

Mrac [35]

Answer:

A Exactly one solution

Step-by-step explanation:

$\left \{ {{6x-3y=9} \atop {6x+y=9}} \right.\\\\\left \{ {{6x-3y=9} \atop {-6x-y=-9}} \right\\\\Then, \\\\-4y=0\\\\\\ y=0\\\\$

Putting y=0 at second equation, we have

$-6x=-9\\\\x=\frac{9}{6} =\frac{3}{2}$

The unique solution is $(\frac{3}{2} , 0)$

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2 years ago

For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative

trapecia [35]

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = $-8(1)+0(3)+1(-3)\\= -11$

Projection of U on V = $\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }$

Similarly projection of V on U

= $\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }$

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3 years ago

Find the value of this expression if x= -6 and y=1. xy^2/-7

Ahat [919]

(-6)(1)∧⁽2/-7⁾= -6 is the answer
Hope it's right

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2 years ago

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