Answer:
A: 6
B: 7.68
C: 28.26
Step-by-step explanation:
A:
D is 6
B:
C = πd
18.84
C:
A = πr 2
28.26
Not 100% sure but hope this helps!
255/56 = 4.55....
You can't have 0.55... buses so you round that up to 1.
Therefore 4+1 = 5 so 5 buses would be the minimum.
K-3 should be the answer because andrew has 3 less than Paul.
Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.
Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.
let
be the probability that commercial cars have rear license plates and
be the probability that connected trucks have rear license plates.
Cars Trucks Total
Total 2049 334 2383
x 239 45 284
p 0.1166 0.1347 0.1191
α=0.05
Hypothesis will be :


It is a left tailed test at 0.05 significance.
Standard errors of p=
=
=
=0.0066
Test statistic Z=p difference/standard error
=(0.1166-0.1347)/0.0066
=-0.0181/0.0061
=-2.967
p value=0.001505<5%
Since p is less than 5% we reject null hypothesis.
We cannot calculate standard deviation so we cannot calculate confidence interval.
Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.
Learn more about z test at brainly.com/question/14453510
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Answer:
.Option A
Step-by-step explanation:
Given that an instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipate studying for an Introduction to Statistics course in the summer.
Minitab results are

Since p value >0.05 our alpha significant level we accept null hypothesis that
difference in means =0
With a p-value of 0.817, that there is no statistically significant evidence of a difference in average anticipated amount of time studying between the men and women
.Option A