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tamaranim1 [39]
4 years ago
10

Ten years ago, the population at Lincoln High School was about 2,000 students. Since then, the population has increased by 25%.

Mathematics
1 answer:
gavmur [86]4 years ago
5 0

Answer:

2,500 students

Step-by-step explanation:

If the population has increased by 25%, the total population of the school is now 125% of what it used to be. Then to figure it out, you find out 125% of 2000 which is 2,500 students!

(Hope that helps :):):)

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15 point reward + brainliest to correct answer!!!
Bumek [7]

Answer:

A: 6

B: 7.68

C: 28.26

Step-by-step explanation:

A:

D is 6

B:

C = πd

18.84

C:

A = πr 2

28.26

Not 100% sure but hope this helps!

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3 years ago
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Melvin is helping his teachers plan a field trip. There are 255 people going on the field trip and each school bus holds 56 peop
anzhelika [568]

255/56 = 4.55....

You can't have 0.55... buses so you round that up to 1.

Therefore 4+1 = 5 so 5 buses would be the minimum.

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3 years ago
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Andrew owns 3 fewer DVDs than Paul. Let K represent number of Paul's DVDs. Write the expression that can be used to find the num
Julli [10]
K-3 should be the answer because andrew has 3 less than Paul.

5 0
3 years ago
7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0
2 years ago
An instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipate stu
Usimov [2.4K]

Answer:

.Option A

Step-by-step explanation:

Given that an instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipate studying for an Introduction to Statistics course in the summer.

Minitab results are

Difference = mu (F) - mu (M)\\T-Test of difference = 0 (vs not =): T-Value = 0.23 \\P-Value = 0.817 \\DF = 46

Since p value >0.05 our alpha significant level we accept null hypothesis that

difference in means =0

With a p-value of 0.817, that there is no statistically significant evidence of a difference in average anticipated amount of time studying between the men and women

.Option A

5 0
4 years ago
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