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lana66690 [7]
3 years ago
15

Solve 1/3+b>3/4. Graph the solution. Pls i need help. i give u over 5 points. i need helppp

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
1/3+b>3/4= 1 over 3rd. + b&gt =bgt; 3/4
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14,000 lb = T <br> Help me plz
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7.0 tons T

Step-by-step explanation:

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Provide the reasons for the following proof. <br> I think the answer is c
pav-90 [236]

Answer:

d. HL CBCTC

Step-by-step explanation:

The hypotenuse and one leg are congruent so the reason for congruency is HL.

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ABCD may or may not be a parellolgram. Line BD bisects line AC, however we cant figure out if line AC bisects line BD.
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Calculate the area of triangle ABC with altitude CD, given A(−7, −1), B(−1, 5), C(0, 0), and D(−3, 3)
Snezhnost [94]

Answer:

A=25 (Rounded)

Step-by-step explanation:

The first step is to find the length of BA which is the base, then you have the find the length of CD, the hight.

To find the distance, you need to use the distance formula which is

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} (It does not matter if A is x1 or is B is x1, it just has to remain consistent)

I am going to first find BA

d=\sqrt{\left({-7}-{-1}\right)^{2}+\left({-1}-{5}\right)^{2}}

Next, subtract accordingly

d=\sqrt{\left({-7}+{1}\right)^{2}+\left({-1}-{5}\right)^{2}}

d=\sqrt{\left({-6}\right)^{2}+\left({-6}\right)^{2}}

Once you do that, you want to square -6 and -6 which will give you

d=\sqrt{\left({36}\right)+\left({36}\right)}

Now add 36 with 36 which will leave you with

d=\sqrt{{72}}

Do that same thing for CD. If you did it right, you should be left with

d=\sqrt{{18}}

to find the area of a triangle, you must use the formula

A=\frac{B*H}{2}

The Base is \sqrt{{72}} (BA) and the Hight is \sqrt{{18}} (CD). substitute to get

A=\frac{\sqrt{{72}}*\sqrt{{18}}}{2}

Multiply the Base by the Hight to get

A=\frac{\sqrt{{1,296}}}{2}

Divide 1,296 by 2 to get

A=\sqrt{{648}}

Which is equal to

A=25.455844122715710878430397035775

Rounding it to the nearest whole number you get

A=25

Hope this helps. Feel free to ask any follow-up questions.

Have a good day! :)

6 0
3 years ago
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