Solve this system of equations: -3x + 6y = 9 x - 2y = -3

Mathematics

2 answers:

Masja [62]3 years ago

7 0

Answer:

(-3+2y,y)

Step-by-step explanation:

I used the app photo math, it gave me this answer and showed the steps.

Leokris [45]3 years ago

4 0

Answer:

No solutions

Step-by-step explanation:

no solutions

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Data management:<br><br> Find n if <br><br> C ( n+ 2 , 2 ) = 36

Lana71 [14]

Please, Karla, explain what "C" and "n" represent. Are you talking about combinations (for example, n+2 objects taken n at a time? Or is C some kind of function? I don't quite see the relationship of this problem to 'data management.'

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3 years ago

For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

3 years ago

36% of what number is 18?

34kurt

18 * 100 / 36 = 200

<span>36% of 50 is 18</span>

7 0

3 years ago

Read 2 more answers

2a+b=15.7 what’s the possible values of b

Fiesta28 [93]

Answer:

b = 15.7 -2a