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Komok [63]
3 years ago
9

Four months ago, Cynthia signed up to receive email notifications to remind her to change her contact lenses,

Mathematics
2 answers:
uranmaximum [27]3 years ago
4 0

Answer:

I think 14n + 9

Step-by-step explanation:

since she got her first email in 9 days and got her second email 14 days later, and it continues to appear every 14 days.

so I think it must be 14n + 9

Firdavs [7]3 years ago
4 0
I think the answer is c
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The length of the garden is 10 feet more than twice its width. The perimeter of the garden is 170 feet.
kumpel [21]

Answer:

Width is 25 ft

length is 60 ft

Step-by-step explanation:

Here, we want to calculate the length and width of the garden

From the question, we are told that the length is 10 ft more than twice its width

So if the width is x ft

Length = 2x + 10

Mathematically, the perimeter of a rectangle i s 2(l + b)

So;

2(x + 2x + 10) = 170

2(3x + 10) = 170

3x + 10 = 85

3x = 85-10

3x = 75

x = 75/3

x = 25 ft

length is;

2(25) + 10 = 50 + 10 = 60 ft

8 0
3 years ago
1. Angle 3 and Angle 6 are examples of which type of angle pair?
mars1129 [50]
Your answer is:Alternate Interior Angles
4 0
3 years ago
If you only have a 1/4 cup measuring cup and a recipe calls for 2 3/4 cups of flour, how many 1/4 cups would you need to use?
Kruka [31]

Answer:

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7 0
3 years ago
Does anyone know what the answer please????
natima [27]

Answer:

I think 25 is this is right

5 0
3 years ago
The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole
lozanna [386]

Answer:

A = 0.75 gram or 1 gram

Step-by-step explanation:

The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole number).

We can use the following formula for half-life of ^{14}C to find out how much is left from the original sample after 2,292 years:  

A = A_{0}e^{-0.000124t}

where:

<em>A</em> is the amount left of an original gram sample after <em>t</em> years, and  

A_{0} is the amount present at time <em>t</em> = 0.

The half-life of  ^{14}C  is the time <em>t</em> at which the amount present is one-half the amount at time <em>t </em>= 0.

If 1 gram of  ^{14}C is present in a sample,  

 Solve for A when t = 2,292:  

Substituting A_{0}  = 1 gram into the decay equation, and we have:  

A = A_{0}e^{-0.000124t}

A = A_{0}e^{-0.000124(2,292)}

A = 0.75 g or 1 g  

6 0
3 years ago
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