Answer:
x=72°
Step-by-step explanation:
We know angles around a point equals 360°
Therefore,
(2x-61)°+(x-11)°+3x°=360°
2x-61+x-11+3x=360°
Collect like terms,
2x+x+3x-61-11=360°
6x-72°=360⁰
Evaluate;
6x=360°+72°
6x=432°
Divide both sides by 6
x=72°
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Answer:
Hiro should have divided both sides of the equation by b
Step-by-step explanation:
Given the formula for area of a triangle (A) = ½bh, Hiro was expected to solve for h.
To find out where Hiro made a mistake, let's solve for h step by step as it ought to be solved.
Thus,
A = ½ bh
==>Multiply both sides by 2:
2*A = 2 * [½bh]
2A = bh
==>Divide both sides by b:
(2A)/b = (bh)/b
(2A)/b = h
h = (2A)/b
The mistake Hiro made was that he subtracted b from both sides of the equation instead if dividing both sides by b.
Hiro should have divided both sides of the equation by b
Answer:
D(1, –5), (7, 1), (–11, 7)
Step-by-step explanation:
The given inequalities are:
y + x ≥ –4
y ≥ x – 6
3y + x ≤ 10
We graph the inequalities as shown in the attachment.
The coordinates of the vertices of the figure formed by the given system of inequalities are:
(1, –5), (7, 1), (–11, 7)
The correct choice is D.
Answer:
D
Step-by-step explanation: