Step-by-step explanation:
since PQRT is a rhombus,
URQ=TPU
y=180-90-24=66
x=180-32-90-24=34
The answer is 1/6 (one-sixth)
It is b only b I think sorry If I am wrong have a good day
Answer:
<u>44 cows and 36 ducks.</u>
Step-by-step explanation:
x is ducks and y is cows.
Assuming both have 1 head each, we can write:
x + y = 80.
Let's assume each x(cow) has 4 legs and each y(duck) has two legs.
Then we can add the numbers of legs:
2x + 4y = 248 legs
Now rearrange x + y = 80 to:
x = 80-y
and substitute:
2x + 4y = 248 legs
2(80-y) + 4y = 248 legs
160 - 2y + 4y = 248 legs
2y = 88 legs
<u>y = 44 [There are 44 cows]</u>
Use this value to find the number of ducks:
x + y = 80
44 + y = 80
<u>y = 36 [There are 36 ducks]</u>
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Check:
Do 44 cows and 36 ducks have a total of 248 legs?
4*44 + 2*36 = 248 ?
176 + 72 = 248?
<u>YES</u>
