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2 years ago

If 8 1/3 of a sum of money is $75, then the total sum of money is?

Mathematics

1 answer:

siniylev [52]2 years ago

3 0

We are required to find the total sum of money given the fraction

The total sum of money is $9

let

<em>Total sum of money</em> = x

8 1/3 × x = $75

25/3 × x = 75

25/3x = 75

Divide both sides by 25/3

x = 75 ÷ 25/3

x = 75 × 3/25

x = (75 × 3) / 25

x = 225 / 25

x = 9

Therefore, the total sum of money is $9

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3 years ago

Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi

aliina [53]

The subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

Given that

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

We have to determine

The subtraction of a polynomial.

According to the question

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

To find the subtraction of the polynomial follow all the steps given below.

Step1; Write the expression as an additive inverse.

$\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)$

Step2; Rewrite terms that are subtracted as the addition of the opposite.

$\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)$

Step3; Group-like terms.

$\rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\$

Step4; the resulting polynomial in standard form is,

$\rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3$

Hence, the subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

To know more about Polynomial click the link given below.

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2 years ago

If 8 1/3 of a sum of mone￼y is $75, then the total sum of money is?

If 8 1/3 of a sum of money is $75, then the total sum of money is?