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Ede4ka [16]
2 years ago
6

Replace the values of mand n to show the solutions of this equation.

Mathematics
1 answer:
umka2103 [35]2 years ago
8 0
(m + n)^2 + 6( m+n) - 5 = 0
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If you score 90% on an assignment, what is the ratio of correct questions to total questions?
artcher [175]
At least like...10,80 or 40
5 0
3 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

#SPJ1

6 0
2 years ago
A direct relationship occurs when
amid [387]
A direct relationship requires a change in the same direction of both variables, answer c.
4 0
3 years ago
Solve the equation 4n = 9
aliina [53]

Answer:

n = 9/4 = 2.250

Step-by-step explanation:

Rearrange:     4*n-(9)=0

Solve:  4n-9 = 0

     4n = 9

       n = 9/4 = 2.250

answer:     n = 9/4 = 2.250

6 0
3 years ago
Read 2 more answers
HELP ON AREA PLZZZZ HELP
Oksana_A [137]

Answer:

70cm

Step-by-step explanation:

Area of triangle:              (5.8x4)/2=11.6

Area of big rectangle:     8x5.8=46.4

Area of small rectangle:  2.4x5=12

12+46.4+11.6=70

7 0
3 years ago
Read 2 more answers
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