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Aliun [14]
3 years ago
10

How many triangles can you make with two side lengths of 6 inches that meet at a 50 degree angle.

Mathematics
2 answers:
Sonbull [250]3 years ago
5 0
<h3>Answer: Exactly One Triangle</h3>

======================================================

Explanation:

Recall that by the SAS (side angle side) congruence theorem, if we know that two pairs of sides are the same length and the angles between them are also congruent, then we can conclude the triangles are congruent. This further means that we can only construct exactly one triangle with two side lengths of 6 inches, and they form a 50 degree angle between them. Applying transformations such as rotations, translations, or reflections will not change the triangle.

Side note: This triangle is isosceles because two sides are the same length. It is not equilateral because we would need to have all three angles to be 60 degrees.

kirza4 [7]3 years ago
5 0

Answer:

One triangle only

Step-by-step explanation:

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denpristay [2]

Answer:

\displaystyle x \approx 38.2 ^{\circ}

General Formulas and Concepts:

<u>Pre-Algebra</u>

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  4. Multiplication
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Equality Properties

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<u>Pre-Calculus</u>

Law of Sines: \displaystyle \frac{sin(A)}{a} =\frac{sin(B)}{b} =\frac{sin(C)}{c}

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Step-by-step explanation:

<u>Step 1: Identify</u>

A = 27°, a = 11

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [LOS]:                     \displaystyle \frac{sin(27^{\circ})}{11} =\frac{sin(x^{\circ})}{15}
  2. Cross-multiply:                        \displaystyle 11sin(x^{\circ}) = 15sin(27^{\circ})
  3. Isolate <em>x</em> term:                         \displaystyle sin(x^{\circ}) = \frac{15sin(27^{\circ})}{11}
  4. Isolate <em>x</em>:                                  \displaystyle x = sin^{-1}(\frac{15sin(27)}{11})
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3 years ago
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gogolik [260]

Answer:

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Step-by-step explanation:

To solve this, we need to start by using c as a standard term instead of in terms of t. Then we simply solve for t.

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7 0
3 years ago
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Viefleur [7K]

Answer:

Rounded to the nearest tenth: x=5.7 in

Rounded to the nearest hundredth: x=5.74 in

Step-by-step explanation:

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Serga [27]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

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