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3 years ago

What is the left-hand limit of this function as x approaches 2? f(x)=x/x-2

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

9514 1404 393

Answer:

B. -∞

Step-by-step explanation:

There is a vertical asymptote at x=2. Left of that line, the denominator is negative. As x approaches 2 from the left, the function approaches negative infinity.

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Volume and surface area are often compared by manufacturers in order to maximize how much of something can go inside of a packag

notka56 [123]

We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem.

Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.

Find the Volume
Volume

l = 27 cm
w = 14 cm
h = 22 cm

V = 27 *14 * 22
V = 8316 cm^3

Find the surface area
SA = 2*l*w + 2*l*h + 2*w*h
SA = 2*27*14 + 2*27*22 + 2*14*22
SA = 756 + 1188 + 616
SA = 2558

Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.

$\frac{SA}{V} = \frac{2*L*W + 2*L*H + 2*W*H}{L*W*H}$

Another way to do this is to consider a cube which might give you a more useful result.

s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2

$\frac{SA_cube}{V_cube} = \frac{6s*s}{s*s*s}$
$\frac{SA}{V} = \frac{6}{s}$

That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.

4 0

3 years ago

A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The

Oksanka [162]

Answer:

a) $[-0.134,0.034]$

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

$s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}$ ,

where $n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19$ .

The mean difference $\mu_1 - \mu_2 = 10.85 - 10.90 = -0.05$ .

The confidence interval is

$(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}$

$= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]$

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0

4 years ago

What brand is better ? Brand A: $2.50 Brand B: 35 for $3.25 Brand C: 50 for $5.25 Brand D: 100 for $10.00

arlik [135]

I belive that the answer should be D) 100 for $10.00 because I had this exact same question one time.

Hope my answer helps!

Thank you for letting me answer!

Thank you,

Florida Mermaid

3 0

3 years ago

Point e is located at -5,2 point m is the reflection of point e what is the distance between e and m

nataly862011 [7]

Answer:

the distance is 10

Step-by-step explanation:

-5,2 to 0,0 is 5

and the refection of -5,2 is 5,2

5,2 to 0,0. is also 5

5+5=10

4 0

3 years ago

519 divided by 6 and 915 divided by 7 and 439 divided by 7 and 812 divided by 9 which one does not have a two digit quotient.

Setler [38]

519/6=86.5

915/7=130.7142

439/7=62.7142

812/9=90.2222

so i think its the 1st on but i may be wrong.

5 0

3 years ago