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Vera_Pavlovna [14]
2 years ago
9

A boat is heading towards a lighthouse, whose beacon-light is 113 feet above the water. From point AA, the boat’s crew measures

the angle of elevation to the beacon, 10^{\circ} ∘ , before they draw closer. They measure the angle of elevation a second time from point BB at some later time to be 21^{\circ} ∘ . Find the distance from point AA to point BB. Round your answer to the nearest foot if necessary.
Mathematics
1 answer:
Blababa [14]2 years ago
3 0

The distance between points A and B and the boat is an illustration of elevation and distance

The distance from point A to point B is 346 feet

<h3>How to calculate the distance AB</h3>

The height of the lighthouse is given as:

h = 113

The distance between point A and the base of the lighthouse is calculated using the following tangent ratio

\tan(10) = \frac{113}{A}

Make A, the subject

A = \frac{113}{\tan(10)}

A = 640.85

The distance between point B and the base of the lighthouse is calculated using the following tangent ratio

\tan(21) = \frac{113}{B}

Make B, the subject

B= \frac{113}{\tan(21)}

B= 294.38

The distance AB, is then calculated as:

AB = A - B

AB = 640.85 - 294.38

AB = 346.47

Approximate

AB = 346

Hence, the distance from point A to point B is 346 feet

Read more about elevation and distance at:

brainly.com/question/7243416

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Marrrta [24]

Answer:

Step-by-step explanation:

B(2,10); D(6,2)

Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)

Rhombus all sides are equal.

AB = BC = CD =AD

distance = √(x2-x1)² + (y2- y1)²

As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x

A(X,0)

AB = AD

√(2-x)² + (10-0)² = √(6-x)² + (2-0)²

√(2-x)² + (10)² =  √(6-x)² + (2)²

√x² -4x +4 + 100 =  √x²-12x+36 + 4

√x² -4x + 104 =  √x²-12x+40

square both sides,

x² -4x + 104 =  x²-12x+40

x² -4x - x²+ 12x = 40 - 104

             8x = -64

               x = -64/8

               x = -8

A(-8,0)

Let C(a,b)

M is AC midpoint

(-8+a/2, 0 + b/2)  = M(4,6)

     (-8+a/2, b/2)  = M(4,6)

Comparing;  

-8+a/2 = 4          ; b/2 = 6

  -8+a = 4*2       ; b = 6*2

  -8+a = 8          ; b = 12

        a = 8 +8

       a = 16

Hence, C(16,12)

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bazaltina [42]

Step-by-step explanation: the 1st answer

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Write the functions by the graphs <br> F(x)=<br> G(x)=<br> H(x)=
Alborosie

Answer:

f(x) = |x|

g(x) = |x| - 2

h(x) = |x| + 3

Step-by-step explanation:

All the functions graphed represent the absolute value functions.

Since function g(x) passes through (0, 0) and (1, 1),

Let the equation of a line passing through these points is,

y = mx + b

Slope of the line passing through these points 'm' = \frac{\text{Rise}}{\text{Run}}=\frac{1-0}{1-0}

m = 1

y-intercept of the line 'b' = 0

Therefore, equation of the line will be,

y = x

And the function representing the two lines (both are the mirror images) joining at the origin will be,

f(x) = |x|

When the parent function is shifted 3 units up, the new function will be

h(x) = |x| + 3

When the parent function is shifted 2 units down,

g(x) = |x| - 2

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