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A= 4 B= 2 C= -1
follow the formula ax^2 + bx + c= 0.
Circled numbers are prime factors comment if you need me to clarify anything
Answer:
x = 6 sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
6^2+ x^2 = 12^2
36 + x^2 = 144
Subtract 36 from each side
x^2 = 144-36
x^2 =108
Take the square root of each side
sqrt(x^2) = sqrt(108)
x = sqrt(36*3)
x = 6 sqrt(3)
<u>Solution</u><u>:</u>


- Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

- Now, transpose 4x and 4 to LHS.

- Now, do the addition and subtraction.

<u>Answer</u><u>:</u>
<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>
Hope you could understand.
If you have any query, feel free to ask.