M=(y2-y1)/(x2-x1)= (3-1)/(4-3) =(2/1)= 2
y=mx+b. plug in one of the points for the second line and solve for b
1=2(3)+b
1=6+b
-5=b
plug b and m back into the equation y=mx+b
y=2x+-5
The solution to the system must make sense when plugged into both equations
C works because
y=x+3; 11=8+3
11=11 and
y=2x-5; 11=2(8)-5
11=11
1 cm=0.01m
75cm=0.75m
3/0.75=4
The completed ratio is 1 to 4
I think the correct answer might be A or D
Answer:
(b) The ratios are both identical (five thirteenths and five thirteenths).
Step-by-step explanation:
The mnemonic SOH CAH TOA can remind you of the relationships between trig functions and sides of a right triangle. In this problem, we're interested in ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
If we name the right angle vertex Q, then these tell you that ...
sin(x°) = OQ/OP = 5/13
cos(y°) = OQ/OP = 5/13
The sin(x°) and cos(y°) ratios are identical. Both are 5/13.
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<em>Additional comment</em>
You may have noticed that the side opposite one of the acute angles in right triangle is the side that is adjacent to the other acute angle. That means <em>the sine of an angle is always equal to the cosine of its complement</em>.
