Answer:
![{27}^{ \frac{1}{3} } = \sqrt[3]{27} = \sqrt[3]{3 \times 3 \times 3} = \boxed{ 3}✓](https://tex.z-dn.net/?f=%20%7B27%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B3%20%5Ctimes%203%20%5Ctimes%203%7D%20%20%3D%20%5Cboxed%7B%203%7D%E2%9C%93)
<h3>3. <em><u>3</u></em> is the right answer.</h3>
Answer:
x = -3
Step-by-step explanation:
Its 160 .................
Answer:
15 rentals
Step-by-step explanation:
You can (and may be expected to) set up an equation that equates the total cost at one store to the total cost at the other store. When you work through the solution of this equation, you find that the "break even" number of rentals is the ratio of the difference in fixed cost (setup fee) to the difference in per-use cost (rental charge).
Here, that ratio is ...
(15.00 -7.50)/(2.25 -1.75) = 7.50/0.50 = 15
15 rentals will make the total costs the same.
20..................................
