1, 3, 3, 4, 5, 6, each x is one of each number below
Answer:
![X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D12%26-24%268%2616%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
A matrix is given by
![A = \left[\begin{array}{cccc}6&-12&4&8\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%26-12%264%268%5Cend%7Barray%7D%5Cright%5D)
Now, we have to find the matrix X if 
⇒ X = 2A
Now, multiplication of a constant with a matrix means multiplication with that constant with all the terms of the matrix.
So, ![X = \left[\begin{array}{cccc}6 \times 2&-12 \times 2&4 \times 2&8 \times 2\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%20%5Ctimes%202%26-12%20%5Ctimes%202%264%20%5Ctimes%202%268%20%5Ctimes%202%5Cend%7Barray%7D%5Cright%5D)
⇒ (Answer)
Answer:
195
Step-by-step explanation:
87+38+40=165
360-165=195
Hope this helps!
If not, I am sorry.
Answer: 81/100
Step-by-step explanation:
I don't guarantee you I am right but..
first, solve for the exponents after substituting the numbers in
3/5 x 3/5 is 9/25
since b's exponent is negative, you change the fraction into its reciprocal and then do it with the exponent but positive
2/3^-3 to 3/2^3 and 3/2 x 3/2 is 9/4
then you mutiply both numbers to get 9/4 x 9/25 is 81/100
