According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:
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Here, n is equal to 66 and by substituting the value to the equation we get:
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k = 7.0444
k ≈ 7
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Answer:
52026353283901
Step-by-step explanation:
The formula for a triangle:
Base times height divided by 2
Equation Form:
b×h÷2
Answer:
<u>125.6 in²</u>
Step-by-step explanation:
Area shaded :
- 2 × Sector (72°)
- 2 x πr² x θ/360
- 2 x 3.14 x 100 x 72/360
- 6.28 x 100 x 1/5
- 20 x 6.28
- <u>125.6 in²</u>
Step-by-step explanation:
In triangle ADE:
sum of all angles is 180.
3x-10+58+42=180
3x+90=180
3x=180-90
3x=90
x=90/3
x=30
As line DA and CB are parallel:
angle D=angle C
angle y=58
In angle BCE, sum of angles is 180.
z+58+42=180
z+100=180
z=180-100
z=80