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rosijanka [135]
3 years ago
9

What is the answer to 13/4 - 5/8=

Mathematics
1 answer:
solmaris [256]3 years ago
6 0
In order to subtract one fraction from another, we need to make the denominator the same in both fractions.  The lowest common denominator is 8, because 4 is a factor of 8.

In order to make the denominators the same, multiply both the numerator and denominator of 13/4 by two.  This keeps the value of the fraction the same, but will equate the denominators.

\frac{13*2}{4*2} = \frac{26}{8}

At this point, we can simply subtract 5/8 from 26/8.

\frac{26}{8}- \frac{5}{8} =  \frac{21}{8}

21/8 cannot be simplified, so it is the answer.
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A group of students are standing in rows. There are as many students in a row as there are rows. If there are 64 students in the
Zanzabum

Answer:

B..im pretty sure

Step-by-step explanation:

First it cant be D because 12 x __ = 64. There is no whole number multiplied by 12 that equals 64. So cross that out. then it's not B because 6 x ___ = 64. So also cross that out. the only thing u have left is 4 and 8. Then u can cross out A because the group of students has to be the same number of rows. Which is 8 x 8 aka B. The answer is B

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What number is 21% of 450?
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Answer:

94.5

Step-by-step explanation:

450 / 100 = 4.5

4.5 * 21 = 94.5

HOPE THIS HELPS

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2 years ago
12 2/6 converted to a mixed number
Kipish [7]

12 2/6 is a mixed number. Though, it can be simplified to 12 1/3


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5 * 10^6 is how many times larger as 5 * 10^4
Alexxandr [17]

\dfrac{5\cdot10^6}{5\cdot10^4}=10^{6-4}=10^2=100

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In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
3 years ago
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