With 2 cubes, there are 3 ways to roll a sum of 4... 1 and 3, 3 and 1, 2 and 2.
with 2 cubes, there are 3 ways to roll a sum of 10....6 and 4, 4 and 6, 5 and 5.
total possible outcomes = (6 * 6 ) = 36
probability of this happening is 6/36 reduces to 1/6
Minus 2 from bothsides
f-2=3g
divide both sides by 3
(f-2)/3=g
g=(f-2)/3
Answer:
To find the sum of a + b where a and b are rational number.
1. when a and b are natural numbers
just add them . for example a =3, b=8
then ,a + b = 11
2. When a and b are whole numbers,
simply add them . for example a= 0, b=8
a+ b = 0 + 8= 8
3. When a and b are integers
for example, a =-1 b=8,
a+ b= -1+ 8 =7,
a=-2, b= -8
a+ b= -2-8=-10
a= -6 , b=2
a+ b= -6 + 2= -4
a= 8, b= -2
a+ b= 8 +(-2) =6
I have written this because Rational number = [Integers{Whole number(Natural number)}]
now when a= Any fraction= and b = Any fraction=
now ,
Find L.C.M of q and v
= if q and v are Co-prime , just multiply them to find their L.C.M.
For example 14,9. LCM=14×9=126
Otherwise, Find factors of q and v . Then take out common factors first and then multiply the remaining with with common factors.For example
q=12 and v=18
12 =2×2×3
18=2×3×3
common factor =2,3
non common=2,3
L.C.M= 2×2×3×3=36
Suppose LCM of q and v = r
then ,
=
=
then ,
a + b=
9(3+5)
if you go through each answer choice you will notice that none of the rest are right
8(3+6) = 24 +48
8(19 +37) = 152 + 296
9(18 +36)= 162 +324
for these you need to rearrange the equations and do substitutions.
#3 = if x+y=5 then you know x = 5-y
now substitute that equation for x in the 2nd one so x + 2y = 8 becomes
5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3
now replace y with 3 in the first equation x = 5-3 so x = 2
so (2,3) is the answer
same type of work for #4
2x-y=6 ,S0 y = 2X+6
so now you have 4x+2(2x+6)=-4
that becomes 4x +4x+12 = -4
8x+8 = 1, x =1
y = 2(1)-6 = -4
so answer is (1,-4)