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Elenna [48]
3 years ago
15

In this equation, what should be the coefficients of the reactants and products?

Chemistry
1 answer:
Dimas [21]3 years ago
7 0
The Coefficients are the numbers that are before a variable/constant
The reactants are l2 and O2
The products are l4O9.
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Convert the following:
Xelga [282]
56 cm^{3} because 1 cm^{3}=1mL
2200000 mg because 1 kg = 1000 mg
2.2 km because 1000 m = 1km
"Kilo" means 1000.
3 0
3 years ago
Which of the following is not a heterogeneous mixture? A.Concrete B.Pizza C.Sugar Water D.Chicken Soup
Arisa [49]
The answer is C. sugar water. Sugar can dissolve in water completely and form the solution. While other three are all heterogeneous mixture.
6 0
3 years ago
A steel cylinder for scuba diving contains 11.1 L of compressed air. The pressure inside the cylinder is
Juli2301 [7.4K]

Answer:

9.28moles

Explanation:

Given parameters:

volume  = 11.1L

pressure  = 204atm

temperature  = 24°C = 24 + 273  = 297K

Unknown:

Number of moles of air in the cylinder  = ?

Solution:

To solve this problem, we apply the ideal gas equation;

         PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant  = 0.082atmdm³mol⁻¹K⁻¹

T is the temperature

Now insert the parameters and find n;

     204 x 11.1  = n x 0.082 x 297

    226.4  = 24.4n

        n  = 9.28moles

4 0
3 years ago
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
Heat energy is useful to us in all the following ways except:
Lelechka [254]

Answer:

Heat energy is transferred to cooler objects to reduce the temperature of those objects.

Explanation:

The fourth option is not correct.

A correct way of writing it would be : " Heat energy is transferred from cooler objects to reduce the temperature of those objects.". When an object loses heat energy, its temperature reduces. Conversely, when an object receives heat energy, its temperature increases.

3 0
3 years ago
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