Answer: hope this helps if so mark me brainlest
Explanation:
The four quantum numbers determine the state of the electron, and are
n
is the distance of the orbital from the nucleus (
1
,
2
,
3
,
4
etc),
l
is the shape of the orbital (
0
→
n
−
1
)
m
l
is the orientation of the orbital in space (
−
l
→
+
l
), and
m
s
is the spin of the electrons inside the orbital (
−
1
2
or
+
1
2
).
The electronic configuration for magnesium is
1
s
2
2
s
2
2
p
6
3
s
2
. The outermost electron is one in the
3
s
orbital, which means that
n
=
3
.
It also means that
l
=
0
, since
s
is basically shorthand for the orbital shape of
l
=
0
.
m
l
can range from
−
l
to
+
l
, but since
l
=
0
, then
m
l
must also be
0
.
Finally,
m
s
can be either one since there are two electrons in the
3
s
orbital and it doesn't really matter which spin you choose.
Putting all of these together, the final quantum numbers of a magnesium atom are
3
,
0
,
0
,
±
1
2
