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guajiro [1.7K]
2 years ago
7

Describe how you would create a Java program that prompted the user to correctly enter a username and password. The username is

not case sensitive, bu
Computers and Technology
1 answer:
schepotkina [342]2 years ago
3 0

Answer:

Explanation:

The program in question would create a new Scanner Object which asks the user for the Username first. It would then save this input into a temporary variable and compare it to the actual username in the database. Since the username is not case sensitive, we would use the toLowerCase() method on both the input and the database username so that they match even if the letters are not the same case structure. If both usernames match then we would move on to ask the user for the Password and compare it with the database password for that user. Since this one is case sensitive we would compare as is. Finally, if both Username and Password match we would print "Hello World" otherwise we would print "Login Failed."

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Answer:

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Explanation:

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3 years ago
A continuous and differentiable function f(x) with the following properties: f(x) is decreasing at x=−5 f(x) has a local minimum
butalik [34]

The continuous and differentiable function where f(x) is decreasing at x = −5 f(x) has a local minimum at x = −2 f(x) has a local maximum at x = 2 is given as: y = 9x - (1/3)x³ + 3.

<h3>What is a continuous and differentiable function?</h3>

The continuous function differs from the differentiable function in that the curve obtained is a single unbroken curve in the continuous function.

In contrast, if a function has a derivative, it is said to be differentiable.

<h3>What is the solution to the problem above?</h3>

It is important to note that a function is differentiable when x is set to a if the function is continuous when x = a.

Given the parameters, we state that

f'(5) < 0; and

x = -5

The local minimum is given as:
x = -3;

the local maximum is given as

x = 3

Thus, x = -3 ; alternatively,

x = 3.  With this scenario, we can equate both to zero.

Hence,

x + 3 = 0;

3-x = 0.

To get y' we must multiply both equations to get:

y' = (3-x)(x + 3)

y'   = 3x + 9 - x² - 3x

Collect like terms to derive:

y' = 3x - 3x + 9 - x²; thus

y' = 9-x²

When y' is integrated, the result is

y = 9x - (x³/3) + c

Recall that

F (-5) < 0

This means that:

9 x -5 - (-5³/3) + c < 0
⇒ -45 + 125/3 + c <0
⇒ -10/3 + c < 0

Collecting like terms we have:
c < 10/3; and

c < 3.33


Substituting C into

f(x) = 9x - x³/3 + c; we have

f(x) = 9x - x³/3 + 3, which is the same as  y = 9x - (1/3)x³ + 3.

Learn more about differentiable functions at:
brainly.com/question/15047295
#SPJ1

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Answer:

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