Answer:
Forward the packet to the next hop router specified by the route network 0.0.0.0
Explanation:
Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
hi there answer is given mar me as brainliest
Answer:
Written in Python
for num in range(1,1001):
sum=0
for j in range(1,num+1):
if num%j==0:
sum = sum + j
if num == sum:
print(str(num)+" is a perfect number")
Explanation:
This line gets the range from 1 to 1000
for num in range(1,1001):
This line initializes sum to 0 for each number 1 to 1000
sum=0
This line gets the divisor for each number 1 to 1000
for j in range(1,num+1):
This following if condition line checks for divisor of each number
<em> if num%j==0:
</em>
<em> sum = sum + j
</em>
The following if condition checks for perfect number
if num == sum:
print(str(num)+" is a perfect number")
Specialized software. hope this helps
