A politician is running for a state representative position. She wants to know what her chances of winning are.

I really need help with this math problem. Can anyone please help.

Sonja [21]

I found these
1,-1,3
-1,1,3
1,1,-3
let me know if it is correct

5 0

4 years ago

Elena is doing a fund-raising mailing for her after-school drama club. She decides to include a brochure in 80% of the letters s

Wittaler [7]

First of all, Elena is kinda dumb why put brochures on only 80%? Nevertheless, 400 letters will not contain a brochure. If you need an explanation just comment that you need one on this.

4 0

3 years ago

If lines p and q are perpendicular and the slope of line p is 2 what is th slope of line q

miss Akunina [59]

perpendicular lines are negative reciprocals of each other so if line p has a slope of 2 then line q has a slope of -1/2.

:)))

5 0

3 years ago

Suppose a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.00

Bingel [31]

Answer:

We conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

Step-by-step explanation:

We are given that a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.005 inch.

Assume that the population is normally distributed: 1.678, 1.681, 1.676, 1.684, 1.676, 1.679, 1.681, 1.681, 1.677, 1.676, 1.681, 1.683.

Let $\sigma$ = population standard deviation of the diameter of a golf ball.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.005 inch {means that the standard deviation of the diameter of a golf ball is more than or equal to 0.005 inch}

Alternate Hypothesis, $H_0$ : $\sigma$ < 0.005 inch {means that the standard deviation of the diameter of a golf ball is less than 0.005 inch}

The test statistics that would be used here One-sample Chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{{\sigma^{2} }}$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.00281 inch

n = sample size = 12

So, the test statistics = $\frac{(12-1)\times 0.00281^{2} }{{0.005^{2} }}$ ~ $\chi^{2} __1_1$

= 3.47

The value of chi-square test statistics is 3.47.

Also, the P-value of test statistics is given by the following formula;

P-value = P( $\chi^{2} __1_1$ < 3.47) = 0.0182

Since, the P-value of the test statistics is less than the level of significance as 0.0182 < 0.05, so we reject our null hypothesis.

Now, at 0.05 significance level the chi-square table gives critical value of 4.575 at 11 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 3.47 < 4.575, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

7 0

3 years ago

What is the equation for the axis of symmetry of a parabola?

nlexa [21]

Answer:

The graph of the parabola is represented by the quadratic function

y = a( x - p )2 + q which has an axis of symmetry represented by the equation of the vertical line x = p.

Step-by-step explanation:

4 0

3 years ago