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FromTheMoon [43]
3 years ago
14

3 ( x + 8) = ? show work please!!

Mathematics
2 answers:
solong [7]3 years ago
7 0

Answer:

Step-by-step explanation:

3(x + 8)

3x + 24

That's all I got. The image is so blurry that I am uncertain how to proceed.

If you are able to describe what the image says, I can definitely answer the question

vodka [1.7K]3 years ago
4 0

Answer:

what does x equal?

Step-by-step explanation:

tell me what x equals and ill answer it

anything for a mlb fan

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The product of -5 and x
lesya692 [45]

Answer:

-5x

Step-by-step explanation:

you multiply them together

(-5)(x)= -5x

4 0
3 years ago
Read 2 more answers
Plz need the answer and how
GarryVolchara [31]

hi!

1) rewrite as a fraction

(2^4/2^2)^3

2) reduce the expression by cancelling out the common factors

so factor out 2^2 out of 2^4

3) multiply by 1 so,

(2^2 * 2^2/ 2^2 * 1)^3

4) continue to cancel out common factors the rewrite the expression to be

(2^2/1)^3

5) then divide 2^2 by 1 so, it will be (2^2)^3

6) lastly simplify the expression so apply the power rule and multiply so it will be 2^2*3

then it will be 2^6

and raise 2 to the power of 6 and you answer is 64

5 0
3 years ago
Read 2 more answers
Solve the equation for y. 6y + 241 = 66<br>I need help finding Y for this Answer​
slavikrds [6]

Answer:

y= -29.16  (the 6 is repeated)

Step-by-step explanation:

6y+241=66

Subtract 241 on both sides

6y= -175

Divide by 6 on both sides

y= -29.16  (the 6 is repeated)

3 0
3 years ago
Find the shaded area​
REY [17]

The parabola <em>y</em> = <em>x</em> ² and the line <em>x</em> + <em>y</em> = 12 intersect for

<em>x</em> ² = 12 - <em>x</em>

<em>x</em> ² + <em>x</em> - 12 = 0

(<em>x</em> - 3) (<em>x</em> + 4) = 0

===>   <em>x</em> = 3

so you can compute the area by using two integrals,

\displaystyle \int_0^3 x^2\,\mathrm dx + \int_3^{12}(12-x)\,\mathrm dx

Then the area you want is

\displaystyle \frac{x^3}3\bigg|_0^3 + \left(12x-\frac{x^2}2\right)\bigg|_3^{12} = \left(\frac{3^3}3-\frac{0^3}3\right) + \left(12^2-\frac{12^2}2 - 12\times3 + \frac{3^2}2\right) \\\\ = \boxed{\frac{99}2}

Alternatively, you can subtract the area bounded by <em>y</em> = <em>x</em> ², <em>x</em> + <em>y</em> = 12, and the <em>y</em>-axis in the first quadrant from the area of a triangle with height 12 (the <em>y</em>-intercept of the line) and length 12 (the <em>x</em>-intercept).

Such a triangle has area

1/2 × 12 × 12 = 72

and the area you want to cut away from this is given by a single integral,

\displaystyle \int_0^3 ((12-x)-x^2)\,\mathrm dx = \int_0^3(12-x-x^2)\,\mathrm dx

The integral has a value of

\displaystyle \left(12x-\frac{x^2}2-\frac{x^3}3\right)\bigg|_0^3 = 12\times3 - \frac{3^2}2 - \frac{3^3}3 \\\\ = \frac{45}2

and so the area of the shaded region is again 72 - 45/2 = 99/2.

7 0
3 years ago
10 increased by the product of p and 2
Nuetrik [128]

10 + 2p

increases by means addition

product means multiplication

3 0
3 years ago
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