Answer:
yes it is :) I hope this helps:)
Answer:
The correct answer would be Ovum.
Explanation:
The reason for Ovum being the correct answer, is because the Ovum is in the lower plant structure, and is the structure that is needed to be fertilized to reproduce gametes.
I believe that shiny is a defining trait
Answer:
1/16
Explanation:
- scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
- ebony (e) is an autosomal mutation recessive to e+ (wild type).
The two genes are independent because they are located on different chromosomes.
<h3>
<u>Parental generation:</u></h3>
True breeding scalloped female wild type for ebony (<em>Xsd Xsd e+e+</em>) mates with a true breeding male mutant only for ebony (<em>Xsd+ Y ee</em>).
The female only produces <em>Xsd e+</em> gametes. The male produces <em>Xsd+ e</em> or <em>Y e</em> gametes.<u> Therefore, the F1 females will have the genotype </u><u><em>Xsd Xsd+ e e+ </em></u><u>and the F1 males will have the genotype </u><u><em>Xsd Y e e+.</em></u>
If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a<em> Xsd Xsd e e</em> genotype and appear in a 1/16 proportion.