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larisa86 [58]
3 years ago
7

PLEASE HELP ASAP 25 POINTS!! Provide a picture if possible! I NEED THIS ASAP

Mathematics
1 answer:
saul85 [17]3 years ago
7 0
I have the same text I need help with this as well
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A scale model of a ramp is a right triangular prism as given in this figure. in the actual ramp, the triangular base has a heigh
kakasveta [241]

The surface area of the actual ramp including the underside is 16.8 ft²

The height of the actual ramp = 1.2 feet  

The height of the model = 6 cm

<h3>What is the surface area of a right triangular prism?</h3>

A right triangular prism is a 3-dimensional triangle with two congruent triangular faces and 3 rectangular faces that connect the triangular.

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Scale factor = 1.2 feet / 6 cm = 0.2 ft/cm

Actual base = 16 cm × 0.2 ft/cm = 3.2 ft

convert the units

9 cm = 9 cm × 0.2 ft/cm = 1.8 ft

10 cm = 10 cm × 0.2 ft/cm = 2 ft

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Surface area of actual ramp = 2(0.5 × 3.2 ft × 1.2 ft) + 2(2 ft × 1.8 ft) + (1.8 ft × 3.2 ft)

= 16.8 ft²

Hence, the surface area of the actual ramp including the underside is 16.8 ft²

Learn more about the area here:

brainly.com/question/25292087

3 0
2 years ago
Nationwide, it is estimated that 40% of service stations have gas tanks that leak to some extent. A new program in California is
fredd [130]

Answer:

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

Step-by-step explanation:

The sample proportion is p2= 7/27= 0.259

and q2= 0.74

The sample size = n= 27

The population proportion = p1= 0.4

q1= 0.6

We formulate the null and alternate hypotheses that the new program is effective

H0: p2> p1   vs  Ha: p2 ≤ p1

The test statistic is

z= p2- p1/√ p1q1/n

z= 0.259-0.4/ √0.4*0.6/27

z=  -0.141/0.09428

z= -1.496

The significance level ∝ is 0.05

The critical region for one tailed test is z ≤ ± 1.645

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

8 0
3 years ago
what are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotensue is 15 units long?
givi [52]
Refer to the diagram shown below.

Given:
m∠A = 19°
c = 15

By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835

cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828

Answer:
The lengths are 4.88, 14.18, and 15.00  (nearest hundredth)  

6 0
3 years ago
The histogram shows the number of yards gained on first downs. How many times did the team gain at least 6 yards on first downs?
BabaBlast [244]

Answer:

8 times

Step-by-step explanation:

Given

The attached histogram

Required

The number of times the team gain at least 6 yards

From the question, the entry that fall in the category of at least 6 yards are:

6\ to\ 8, 9\ to\ 11 and 12\ to\ 14

Their frequencies are:

5, 2 and 1 respectively

So, the number of times is:

Times = 5 + 2 + 1

Times =8

4 0
2 years ago
Read 2 more answers
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
KATRIN_1 [288]

Answer: x^{\frac{2}{3} }

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

(x^{a})(x^{b}) = x^{a + b} <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

(x^{a})^{b} = x^{(a)(b)} <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

<em />

Let's apply it!

First, let's simplify what's inside the parenthesis.

x^{\frac{4}{3} } x^{\frac{2}{3} } <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

x^{\frac{4}{3} + \frac{2}{3} } = x^{\frac{6}{3} } = x^{2}

Now we have (x^{2})^{\frac{1}{3} }. Let's use the second rule.

(x^{2})^{\frac{1}{3} } = x^{\frac{2}{3} }

Hope this helps! :^)

7 0
3 years ago
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