What is the range of the relation below?

Pls help I’ll make brainlest and give extra points

allochka39001 [22]

Answer:

p>-3 open circle going to the right

$m\leq -4$ closed circle going to the left

n<5 open circle going to the left

$h\geq 2$ closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

Step-by-step explanation:

Before I answer these here are some good notes

If the inequality sign is < or > then the circle is going to be open

If the inequality sign is $\leq or\geq$ then the circle is going to be closed

If the inequality sign is facing the variable (ex: x>3) then the line is going to be going to the right

If the inequality sign is facing the constant (ex: x<3) then the line is going to be going to the left

p>-3 open circle going to the right

$m\leq -4$ closed circle going to the left

n<5 open circle going to the left

$h\geq 2$ closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

6 0

3 years ago

How do i find the volume of the last one? density= 2.7g/cm^3 mass= 0.85g

Liula [17]

You do mass divided by density

4 0

3 years ago

1. Determine a rule that could be used to explain how the volume of a

Eva8 [605]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- We will use the basic formulas for calculating the volumes of two solid bodies.

- The volume of a cylinder ( V_l ) is represented by:

$V_c = \pi *r^2*h$

- Similarly, the volume of cone ( V_c ) is represented by:

$V_c = \frac{1}{3}*\pi *r^2 * h$

Where,

r : The radius of cylinder / radius of circular base of the cone

h : The height of the cylinder / cone

- We will investigate the correlation between the volume of each of the two bodies wit the radius ( r ). We will assume that the height of cylinder/cone as a constant.

- We will represent a proportionality of Volume ( V ) with respect to ( r ):

$V = C*r^2$

Where,

C: The constant of proportionality

- Hence the proportional relation is expressed as:

V∝ r^2

- The volume ( V ) is proportional to the square of the radius. Now we will see the effect of multiplying the radius ( r ) with a positive number ( a ) on the volume of either of the two bodies:

$V = C*(a*r)^2\\\\V = C*a^2*r^2$

- Hence, we see a general rule frm above relation that multiplying the result by square of the multiple ( a^2 ) will give us the equivalent result as multiplying a multiple ( a ) with radius ( r ).

- Hence, the relations for each of the two bodies becomes:

$V = (\frac{1}{3} \pi *r^2*h)*a^2$