The answer is 2z+3. The like terms are 5z and -3z so you can subtract them and get 2z. Thus, the answer is 2z+3
Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
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hope this helps
Answer:
if they all have the same angle they r congruent
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Answer:
Wait can you re expain in the comments
Step-by-step explanation:
Answer: Choice C) Infinitely many solutions
If you solve the first equation for y, you get
2y = 14 - 2x
2y = 14 + (-2x)
2y = -2x + 14
2y/2 = (-2x)/2 + 14/2 ... divide every term by 2
y = -x + 7
This result of y = -x+7 is identical to the second equation in the system. So the two graphs are going to be the same. We only produce one line. One graph is right on top of the other. The two lines will intersect infinitely many times. Any point on the blue line is a solution to the system.
