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3 years ago

9. Write the equation of the line in slope-intercept form given the following:

Mathematics

1 answer:

dusya [7]3 years ago

8 0

Answer:

y=1x+1

Step-by-step explanation:

We already know the Y intercept is 1 from the first set of points given

The change in x is 2 and the change in Y is also 2 so when you make the slope equation y/x you get 1

Pluggin in the numbers you get: y=1x+1

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A jewelry box contains 13 gold earrings, 10 silver earrings and 12 titanium

gulaghasi [49]

Answer:

The probability is 406/625

Step-by-step explanation:

If they are of different materials, we have the following combinations of selection;

(gold and silver) or ( silver and titanium) or (gold and titanium )

The number of earrings present is 13 + 10 + 12 = 25

Probability of selecting a gold earring is 13/25

Probability of a silver is 10/25

Probability of a titanium is 12/25

Substituting these into the probabilities, we have;

(13/25 * 10/25) + (10/25 * 12/25) + (13/25 * 12/25)

= 130/625 + 120/625 + 156/625 = 406/625

8 0

3 years ago

Simplify the following: <br> 2m x 8n

tresset_1 [31]

Answer:

16mn

Step-by-step explanation:

8 0

3 years ago

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What are a and b worth in abxaxb=bbb

nignag [31]

Ab*a*b=bbbthat us the same as 2a*2b=3b now subtract 2b from both sides to get 2a=b that means that a=1/2b you are welcome : )

3 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

Hello hello I need help asap

irina1246 [14]

13/4 and 3 1/4
Hope this helps

5 0

3 years ago

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