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Vinil7 [7]
3 years ago
5

Two tangents drawn to a circle from a point outside it, are equal in length.prove it.​

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0
Given: A circle with centre O; PA and PB are two tangents to the circle drawn from an external point P.
To prove: PA = PB
Construction: Join OA, OB, and OP.
It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.
OA⊥PA
OB⊥PB
In △OPA and △OPB
∠OPA=∠OPB (Using (1))
OA=OB (Radii of the same circle)
OP=OP (Common side)
Therefor △OPA≅△OPB (RHS congruency criterion)
PA=PB
(Corresponding parts of congruent triangles are equal)
Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal.
The length of tangents drawn from any external point are equal.
So statement is correct

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Answer:

-5y + 8x

Step-by-step explanation:

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How do I find the x and the y
mart [117]

Answer:

x = 22

y = 35

Step-by-step explanation:

Because its an isosceles triangle, you know the base angles are equal so:

3x - 11 = 2x + 11

Solving:

subtract 2x from both sides

x-11=11

add 11 to both sides

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Next, find the angle measures of the two base angles:

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To find y, you know that the interior angles of the whole triangle add up to 180, so you have

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solving,

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subtract 110 from both sides

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Daniel [21]

Answer:

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Step-by-step explanation:

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Q = {1.1, 1.4, 1.7, 2.1, 2.3}

Here, the median is 1.7 ( The middlemost value is the required median.)

Now, if s < 1.7,

Q= {1.1, s, 1.4, 1.7, 2.1, 2.3}

Now for the least value, median = 1.55

If s > 1.7,

Q = {1.1, 1.4, 1.7, 2.1, s, 2.3}

Now for the greatest value, median = 1.9

Absolute difference between the medians = |1.9 -1.55|

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