Answer:
a = 1.5
b = 1.75
Step-by-step explanation:
First, we need to solve
and replace the result in the initial equation as:

Then, this equality apply only if the coefficient of
is equal in both sides and the constant is equal in both sides.
It means that we have two equations:

So, using the first equation and solving for a, we get:

Finally, replacing the value of a in the second equation and solving for b, we get:

Answer:
X >= 1
Step-by-step explanation:
Answer:
Step-by-step explanation:
The height of the marshmallow (in feet) is represented by the equation h=−16t2+8t+48,
where t is the time (in seconds) after he throws the marshmallow.
The equation is a quadratic equation. When the marshmallow hits the ground, its height from the ground will be zero. Therefore
−16t^2+8t+48 = 0
- 2t^2 + t + 6 = 0
Multiplying through by the negative sign. It becomes
2t^2 - t - 6 = 0
2t^2 + 3t - 4t - 6 = 0
t(2t + 3) - 2(2t + 3) = 0
(t - 2)(2t + 3) = 0
t - 2 = 0 or 2t + 3 = 0
t = 2 or t = - 3/2
The time cannot be negative
So it will take 2 seconds to hit the ground
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3
#6. A and B