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3 years ago

A circle has an area of 3.14 cm^2 . What is its radius?

Mathematics

2 answers:

Anni [7]3 years ago

6 0

Answer:

Cant be determined

Step-by-step explanation:

You would need the diameter to figure this out

Mice21 [21]3 years ago

3 0

The radius of the circle is 1 cm, if the circle has an area of 3.14 $cm^{2}$ .

Step-by-step explanation:

The given is,

Area of the circle is 3.14 $cm^{2}$ ,

Step:1

The formula for Area of circle,

A = π $r^{2}$ ....................(1)

where,

π - 3.14

r - Radius of circle

Step:2

From the given,

Area, A = 3.14 $cm^{2}$

Eqn (1) becomes,

3.14 = 3.14 × $r^{2}$ (∵ π = 3.14 )

$\frac{3.14}{3.14}$ = $r^{2}$

$r^{2}$ = 1

r = $\sqrt{1}$

= 1

r = 1 cm

Radius of circle, r = 1 cm

Result:

Thus the radius of the circle is 1 cm, if the area of circle is 3.14 $cm^{2}$ .

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The diagram shows the net of a juice box. The box is a rectangular prism.

Hoochie [10]

Answer:

269.6 square centimeters

Step-by-step explanation:

The correct question is

The diagram shows the net of a juice box. the box is a rectangular prism. what is the surface area of the juice box? 6.4 cm 4 cm 10.5 cm

we know that

The surface area of a rectangular prism is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

we have

$L=6.4\ cm\\W=4\ cm\\H=10.5\ cm$

Find the area of the base B

$B=LW$

substitute the given values

$B=(6.4)(4)=25.6\ cm^2$

Find the perimeter of the base P

$P=2(L+W)$

substitute the given values

$P=2(6.4+4)=20.8\ cm$

Find the surface area

$SA=2B+PH$

substitute

$SA=2(25.6)+(20.8)10.5=269.6\ cm^2$

6 0

3 years ago

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

$x+x+3+x^2+6x+9=77$ $[\because (a+b)^2=a^2+2ab+b^2]$

$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

$x^2+8x-65=0$

Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

6 0

3 years ago

13 ft 8 ft Jjjjjjjjjjjjj

Yuri [45]

Answer: if it is area 108ft2

Step-by-step explanation:

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6 0

3 years ago

What is the first step in the constitution of a line perpendicular to AB and passing through an external point M?

NikAS [45]

take your compass on a point on your line. then draw a circle. take the 2 points in which the circle hit the line and draw 2 circles larger than half the distance between he 2 points. take the point that they intersect and and connect it to the line and you point M and it is purpendicular. does that make sense?

7 0

3 years ago

Which expressions are equivalent to Negative 9 (two-thirds x + 1)? Check all that apply.

Sav [38]

Answer:

$-9(\frac{2}{3}x) + 9(1)\\ \\-6x + 9$