<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>5</em><em>0</em><em>0</em><em>.</em>
<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>y</em><em>o</em><em>u</em><em>.</em><em>.</em>
Given:
Length of chords of one segment = 11 and 8
Length of chords of other segment = 2 and x
To find:
The value of x.
Solution:
<em>If two chords intersect each other inside a circle, the products of length their segments are equal.</em>
Divide by 2 on both sides.
Switch the sides.
The value of x is 44.
Answer: one number is 104, the first number is 26 and the third number is 126
How to:
Let’s say the “first number” is Y, the “second number” is X, and the “third number” is Z. This makes Y=4x and Z=x+100. Then put it into an equation to find the sum: X+4x+x+100=256. Take away 100 from both sides of the equation and combine the like terms (the X’s). That leaves 6x=156. Then divide both sides by 6 to get x alone which is x=26. That is the first number. To find Y just multiply X by 4 and that’s Y=104. And lastly add 100 to x which is Z=126.
Length is 120 and the width is 60, because 60×2= 120 and when you add 120+60=180
