Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
4.4 + (4 × 14 + 8.6)
Follow the order of operations (PEMDAS).
4.4+(56+8.6)
4.4+(64.6)
answer: 69
<span>The mid-point or the number that divides a series of values into two groups of equal numbers of values is referred to as the median. To get the median value, first sort the numbers from highest to lowest or lowest to highest and then pick the middle number. However, for even numbered sets of numbers, take the average of the two middle numbers and the resulting number is the median. </span>
