Answer:
A fruit stand has to decide what to charge for their produce.
They need $ 5.30 for 1 apple and 1 orange.
They also need $ 7.30 for 1 apple and 2 oranges.
TO DETERMINE
To put this information into a system of linear equations.
TO find a unique price for an apple and an orange
EVALUATION
Let the price of an apple = x and price of an orange = y
So From the first condition that they need $ 5.30 for 1 apple and 1 orange we get
\sf{x + y = 5.30}x+y=5.30 - - - - Equation 1
Again from second condition that they need $ 7.30 for 1 apple and 2 oranges we get
\sf{x + 2y = 7.30}x+2y=7.30 - - - - Equation 2
So the required Set of linear equations are
x + y = 5.30
x + 2y = 7.30
Equation (2) - Equation (1) we get
y = 2
From Equation (1) we get
x = 5.30 - 2 = 3.30
Hence price of an apple = $ 3.30
The price of an orange = $ 2
