You're looking for c, so you want to isolate it or get it by itself. To get rid of the /3 you multiply since the opposite of division is multiplication and to get rid of it, you do the opposite (like -9 you would add 9 to get it to 0). Now you are left with -19+c = 24 (the 24 is 8*3 because what you do to one side you do to the other. Now you get c by itself so you add 19 to both sides which leaves you with C= 43. Sorry if this was confusing!
Following expressions will have negative product
![(\frac{1}{2})(-\frac{1}{2})\ and\ (-\frac{1}{2})(\frac{1}{2})](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%28-%5Cfrac%7B1%7D%7B2%7D%29%5C%20and%5C%20%28-%5Cfrac%7B1%7D%7B2%7D%29%28%5Cfrac%7B1%7D%7B2%7D%29)
Following expressions will have positive product
![(-\frac{1}{2})(-\frac{1}{2})\ and\ (\frac{1}{2})(\frac{1}{2})](https://tex.z-dn.net/?f=%28-%5Cfrac%7B1%7D%7B2%7D%29%28-%5Cfrac%7B1%7D%7B2%7D%29%5C%20and%5C%20%28%5Cfrac%7B1%7D%7B2%7D%29%28%5Cfrac%7B1%7D%7B2%7D%29)
Further explanation:
We will see at each expression one by one
First expression is:
![(-\frac{1}{2})(\frac{1}{2})](https://tex.z-dn.net/?f=%28-%5Cfrac%7B1%7D%7B2%7D%29%28%5Cfrac%7B1%7D%7B2%7D%29)
In the given expression one term is positive and one term is negative. The product of negative and positive terms is negative.
Second Expression is:
![(-\frac{1}{2})(-\frac{1}{2})](https://tex.z-dn.net/?f=%28-%5Cfrac%7B1%7D%7B2%7D%29%28-%5Cfrac%7B1%7D%7B2%7D%29)
Both terms are negative and the product of two negative terms is positive.
Third Expression is:
![(\frac{1}{2})(-\frac{1}{2})](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%28-%5Cfrac%7B1%7D%7B2%7D%29)
The expression has one positive and one negative term so the product will be negative
Fourth Expression is:
![(\frac{1}{2})(\frac{1}{2})](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%28%5Cfrac%7B1%7D%7B2%7D%29)
Both terms are positive so the product will also be positive
Keywords: Product, Expressions
Learn more about expressions at:
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Answer:
c
Step-by-step explanation:
For part a: you just need to find how far the vertex has been moved from the origin, or the point (0,0). As the vertex is at the point (2,-3), it has been translated right 2 horizontally and down 3 vertically.
For part b: you use the info found in part a to create the equation in the form of y=A(x-h)^2+k. In this case, A =1, so you can ignore it. The h value is the horizontal distance the vertex has been moved. Since it has been moved right 2, this part of the equation would be (x-2). I know it seems like it should be plus 2, but values in parentheses come out opposite. For the k value, find the vertical shift, which is down3, or -3.
Now that you have h and k, substitute them back into the equation.
Your final answer for part b is: y=(x-2)^2 -3.
Answer:
i dont know
Step-by-step explanation: just for points sorry :(