Its the final brain cell.<br> (intense music)<br> help this is easy WiLL mArK bRaiNLieSt

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Burka [1]

Answer: d) 0.9693

<u>Step-by-step explanation:</u>

refer to the z-table attached.

The table shows the percent from the MEAN. The percent below the mean is 50% so that needs to be added to the value in the table.

Look on the left side for 1.8 and the top for 0.07 (which is 1.87).

The value is 0.4693 --> add 0.5 to that value to get 0.9693.

6 0

3 years ago

A bowl contains 11 white stones and 3 black stones. One stone is chosen and not replaced, then another stone is chosen. What is

Nataly [62]

Answer:

11/ 14 chance that you will pick a white stone

3/14 chance to picka a black stone

Step-by-step explanation:

Hope that helps

7 0

3 years ago

Read 2 more answers

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%284%20%2B%206i%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(4 + 6i) {}^{2} " alt="(4 +

34kurt

Answer:

$36i^{2}+48i+16$

Step-by-step explanation:

$(4+6i)^{2}$ is essentially $(4+6i)(4+6i)$ (you are squaring $(4+6i)$ , so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

$(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$

( $(4*4)+(4*6i)+(6i*4)(6i*6i)$ )

After doing so, you would end up with $16+24i+24i+36i^{2}$ , and after combining like terms, $16+48i+36i^{2}$ .

To write the expression in standard form, though, just order the terms from highest to lowest power!

5 0

3 years ago

Write your answer without using negative exponents

Reil [10]

Answer:

$\frac{1}{ {u}^{42} }$

Step-by-step explanation:

From law of indices

5 0

3 years ago

Its the final brain cell. (intense music) help this is easy WiLL mArK bRaiNLieSt