2 years ago

Consider the line y=5x-4.

Mathematics

1 answer:

Bezzdna [24]2 years ago

3 0

Answer:

Parallel= y-5x-3

perpendicular=y=5x

Step-by-step explanation:

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8. At the beginning of the semester, a professor tells students that if they study for the tests, then there is a 55% chance the

Bezzdna [24]

Answer:

Step-by-step explanation:

S= studies for

B= score of b or higher

we want P(S|B)

Using Bayes' theorem we can solve for the probability

$S|B=\frac{B|S*S}{B|S*S+B|S'*S'}=\frac{.55*.6}{.55*.6+.2*.4}=0.80487804878$

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2 years ago

Evaluate the expression when c=9 and d=8. 4c+d please help

guapka [62]

Answer:

Step-by-step explanation

4c + d

this is an expression and since they provided c and d it is easy to solve

c = 9 and d = 8. You need to plug in c and d into the expression to solve the problem.

4(9) + (8)

4 times 9 is 36 so it leaves you with 36 + 8

36 + 8 = 44

I hope this helps but basically the concept is just plugging in the numbers in place of the variables. For future problems plug in the numbers given where the variables are.

7 0

3 years ago

J=b-q/g solve for b.

Zigmanuir [339]

Answer:

$j = b - \frac{q}{g} \\ j + \frac{q}{g } = b \\ b = \frac{gj + q}{g} \\ thank \: you$

7 0

2 years ago

IM GIVING BRAINIEST TO THE FIRST CORRECT ANSWER !!! HURRY.

dexar [7]

Answer:

-1,3

Step-by-step explanation:

1 left and 3 up

8 0

3 years ago

Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

Gre4nikov [31]

The formula of the midpoint of HE:
$\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)$

We have H(0; 0) and E(2a; 2a). Substitute:
$\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)$

4 0

3 years ago

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