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maw [93]
2 years ago
12

HELP EDCITEE !! PLEASE !!!

Mathematics
1 answer:
Mariana [72]2 years ago
3 0

Answer:

75.3074525 dgrees

Step-by-step explanation:

law of sines

29/sin(115 degrees) = 13/sin(B)

==> B = 0.418374736 rad

or 75.3074525 dgrees

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1. Explain whether each following example is proportional or non-proportional.
skelet666 [1.2K]

9514 1404 393

Answer:

  (a), (b), (c) are non-proportional

  (d) is proportional

Step-by-step explanation:

An equation or graph with a non-zero y-intercept is non-proportional. That is true for (a), (b), (c).

The table of (d) is proportional, with a constant of proportionality of 6.5.

__

<em>Comment on (c)</em>

In a proportional relation, price would go up with quantity, not down. If the prices both end in 9, one cannot be double the other, as would be required for the price of a gallon to be proportional to the price of a half-gallon.

3 0
3 years ago
Which point on the number line best represents √67?
Zepler [3.9K]

Answer: C

Step-by-step explanation: The square root of 67 is 8.18

4 0
2 years ago
10. Contacts. Assume that 30% of students at a university
jonny [76]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) A normal model with mean 0.3 and standard deviation of 0.0458 should be used.

b) There is a 0.2327 = 23.27% probability that more than one third of this sample wear contacts.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 30% of students at a university wear contact lenses, hence p = 0.3.
  • We randomly pick 100 students, hence n = 100.

Item a:

np = 100(0.3) = 30 \geq 10

n(1 - p) = 100(0.7) = 70 \geq 10

Hence a normal model is appropriated.

The mean and the standard deviation are given as follows:

\mu = p = 0.3

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.3(0.7)}{100}} = 0.0458

Item b:

The probability is <u>1 subtracted by the p-value of Z when X = 1/3 = 0.3333</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3333 - 0.3}{0.0458}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

1 - 0.7673 = 0.2327.

0.2327 = 23.27% probability that more than one third of this sample wear contacts.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

5 0
2 years ago
How do you write 2 thousands 9 tens and 18 ones in standard form
Dovator [93]
2 thousands 9 tens and 18 ones in standard form is 2,108.
5 0
3 years ago
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D<br> B<br> 3x43<br> IC<br> 4x+2<br> Determine the value of mZDCB.
Studentka2010 [4]

Step-by-step explanation:

3x+3² , you might want a second opinion I am no good at math but I tried to work it out to see if I would get it right so don't quote me on this and put it down for an answer get a second opinion please

7 0
3 years ago
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