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Aneli [31]
3 years ago
15

Please help im really dumb also how do you delete other peoples post on this app

Mathematics
2 answers:
Setler [38]3 years ago
6 0

Answer:

I don't think you can delete them only rate them. and all you have to do is get 39÷0.4

PIT_PIT [208]3 years ago
3 0
It would be 15.60 ,correct me if am wrong :)
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PLEASE! PLEASE! PLEASE! HELP!!!!! also please dont put silly answers i grinded for these points
Eddi Din [679]

Answer:

m <ADB = <u>90° + ½ r</u>

Step-by-step explanation:

explanation attached. brainliest would be nice.

6 0
3 years ago
True or False Atomic theory has changed over time
jolli1 [7]

Answer:

True

Step-by-step explanation:

As modern science has advanced we're able to learn more about what makes up matter. Hope this helps :)

5 0
3 years ago
Identify the variable expression that is not a polynomial. A. 23 B. + 2 C. y + 1 D. x12
myrzilka [38]
A polynomial consists of several terms so A.23
4 0
3 years ago
I NEED HELP PLEASEE
xenn [34]

\bf \cfrac{1+cot^2(\theta )}{1+csc(\theta )}=\cfrac{1}{sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\implies \cfrac{1+\frac{cos^2(\theta )}{sin^2(\theta )}}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{sin^2(\theta )+cos^2(\theta )}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}

\bf \cfrac{1}{\underset{sin(\theta )}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}\cdot \cfrac{~~\begin{matrix} sin(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{sin(\theta )+1}\implies \cfrac{1}{sin^2(\theta )+sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\ne \cfrac{1}{sin(\theta )}~\hfill

5 0
3 years ago
Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use
spayn [35]
If both polynomials are the same degree, divide the coefficients of the highest degree terms. If the polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote<span>.</span>The curves approach these asymptotes but never cross them. To find the vertical asymptote(s) of a rational function, simply set the denominator equal to 0 and solve for x.Finding Slant Asymptotes<span> of Rational Functions.

A </span>slant (oblique) asymptote occurs<span> when the polynomial in the numerator is a higher degree than the polynomial in the denominator. To </span>find the slant asymptote<span> you must divide the numerator by the denominator using either long division or synthetic division.
</span>
3 0
3 years ago
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